16x^2+9x^2=207^2

Solution for 16x^2+9x^2=207^2 equation:

16x^2+9x^2=207^2

We move all terms to the left:

16x^2+9x^2-(207^2)=0

We add all the numbers together, and all the variables

25x^2-42849=0

a = 25; b = 0; c = -42849;
Δ = b2-4ac
Δ = 02-4·25·(-42849)
Δ = 4284900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4284900}=2070$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2070}{2*25}=\frac{-2070}{50}
=-41+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2070}{2*25}=\frac{2070}{50}
=41+2/5
$